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The value of `tan^-1(1/3)+tan^-1(2/9)+tan^-1(4/33)+tan^-1(8/129)+....n` terms is: |
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Answer» `T_r=tan^(-1)((2^(r-1))/(2^(2r-1)+1))` `r_1=1/3` `r_2=2/9` `r_3=4/33` `2^(r-1)=2*2^(r-1)-2^(r-1)=2^r-2^(r-1)` `T_r=tan^(-1)((2^r*2^(r-1))/(1+2^r*2^(r-1)))` `T_1=tan^(-1)(2)-tan(1)` `T_2=tan^(-1)(4)-tan^(-1)(2)` `T_3=tan^(-1)(8)-tan^(-1)(4)` . . . `T_n=tan^(-1)(2^n)-tan^(-1)(2^(n-1))` `T_1+T_2+t_3+...+T_n=tan^(-1)2^n-pi/4` option 1 is correct. |
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