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The value of the integral `int_(0)^(1)(x^(3))/(1+x^(8))dx` isA. `(pi)/(2)`B. `(pi)/(4)`C. `(pi)/(8)`D. `(pi)/(16)` |
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Answer» Put `x^(4)=t` and `4x^(3)dx=dt`. `[x=0impliest=0]` and `[x=1impliest=1]` `:. I=(1)/(4)int_(0)^(1)(dt)/((1+t^(2)))=(1)/(4)[tan^(-1)t]_(0)^(1)=(1)/(4)[tan^(-1)-tan^(-1)0]=((1)/(4)xx(pi)/(4))=(pi)/(16)` |
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