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The value of the integral ` int _(0)^(pi//2) log | tan x| dx `isA. ` pi log 2`B. 0C. `-pi log 2`D. None of these |
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Answer» Correct Answer - B Let `l=int_(0)^(pi//2)log|tanx|dx" …(i)"` `rArr" "l=int_(0)^(pi//2)log|tan((pi)/(2)-x)|" …(ii)"` On adding Eqs. (i) and (ii), we get `2l=int_(0)^(pi//2)log|tanxcotx|dx` `=int_(0)^(pi//2)log1dx=0` `rArr" "l=0` |
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