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The value of Z1^‘ in terms of Z1, Z2 from the circuits shown below is?(a) Z1^‘=(m Z2(Z2 4 m)/(1-m^2))/m Z1(Z2 4 m/(1-m^2))(b) Z1^‘=(m Z1(Z2 4 m)/(1-m^2))/m Z2(Z2 4 m/(1-m^2))(c) Z1^‘=(m Z1(Z2 4 m)/(1-m^2))/m Z1(Z2 4 m/(1-m^2))(d) Z1^‘=(m Z1(Z2 4 m)/(1-m^2))/m Z1(Z1 4 m/(1-m^2))The question was posed to me in a national level competition.My question is based upon m-Derived T-Section in division Filters and Attenuators of Network Theory |
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Answer» CORRECT option is (c) Z1^‘=(m Z1(Z2 4 m)/(1-m^2))/m Z1(Z2 4 m/(1-m^2)) To ELABORATE: As Zoπ = Zoπ^’, √(Z1Z2/(1+Z1/4 Z2))=√(((Z1^‘ Z2)/m)/(1+(Z1^‘)/(4 Z2/m))). On SOLVING, Z1^‘=(m Z1(Z2 4 m)/(1-m^2))/m Z1(Z2 4 m/(1-m^2)). |
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