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The vapour pressure of a certain liquid is given by the equation: `Log_(10)P = 3.54595 - (313.7)/(T) +1.40655 log_(10)T` where P is the vapour pressure in mm and `T =` Kelvin Temperature. Determine the molar latent heat of vaporisation as a function of temperature. calculate the its value at `80K`. |
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Answer» Correct Answer - `DeltaH = 1659.9` Cal. At `80 K, DeltaH = R[313.7 xx 2.303 +1.40655 T]` `(d InP)/(dT) = (DeltaH)/(RT^(2))` ...(i) `logP = 3.54595 - (313.7)/(T) +1.40655 logT` `In P = 3.54595 xx 2.303 - (313.7)/(T) xx 2.303 +1.40655 In T` `(d In P)/(dT) = (313.7 xx 2.303)/(T^(2)) +(1.40655)/(T)` ...(ii) Compairing equation (i) & (ii) `DeltaH = R[313.7 xx 2.303 +1.40655 T]` at `T = 80 K` `DeltaH = 1659.9 Cal`. |
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