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The vapour pressure of a dilute aqueous solution of glucose is 740 mm of mercury at 373 K. The mole fraction of the solute is:A. `(1)/(20)`B. `(1)/(38)`C. `(1)/(76)`D. `(1)/(760)` |
Answer» Correct Answer - B `(p^(@)-p_(s))/(p^(@)) = x_(B)` (mole fraction of the solute) At `373 K (100^(@)C) V.P.` of pure water, `p^(@) = 760`mm of Hg `:.` mole fraction of solute `= (760 - 740)/(760) = (1)/(38)` |
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