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The vapour pressure of a solution of 5g of non-electrolyte in 100g of water at a particular temperature is `2985 N m^(-2)`. The vapour pressure of pure water at that temperature is `3000 N m^(-2)`. The molecular weight of the solute isA. `180`B. `90`C. `270`D. `200` |
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Answer» Correct Answer - a `(P_(A)^(@)-P_(S))/P_(S)=W_(B)/M_(B)xxM_(A)/W_(A)` `(3000-2985)/(2985)=((5g))/((M_(B)))xx((18g))/((100g))` `M_(B)=180 (by calculation)` |
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