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The vapour pressure of benzene at `90^(@)C` is `1020` torr. A solution of `5g` of a solution in `58.5g` benzene has vapour pressure 990 torr. The molecular weight of the solute is? |
Answer» `(P^(0)-P_(S))/(P_(S)) =(w xx M)/(m xx W) rArr (1020 -990)/(990) = (5 xx 78)/(m xx 58.5) rArr m = 220` | |