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The vapour pressure of benzene at a certain temperature is `640 mm` of Hg A non-volatile and non-electrolyte solid weighing `0.175g` is added to `39.08g` of benzene .the vapour pressure of the solution is`600 mm` of Hg.What is the molecular weight of solid substance ?A. `49.50`B. `59.6`C. `69.5`D. `79.8` |
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Answer» Correct Answer - C `(P_(0)-P_(s))/(P_(0))=((w)/(m))/((w)/(m)+(W)/(M)) because (W)/(M)gt(w)/(m)` `rArr(640-600)/(640)` `=(w)/(m)xx(M)/(W)rArr(40)/(640)=(2.175xx78)/(mxx39.08)` `m=(2.175xx78)/(39.08)xx(640)/(40)` `m=69.45` |
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