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The vapour pressure of ethly acetate and ethly propionate are72.8mm abd 27.7mm of Hg respectively. A solution is prepared by mixing 25 g ethly acetate and 50 g of ethly propionate. Assuming to be ideal, calculate its vapour pressure. |
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Answer» No. of moles of `CH_(3)COOC_(2)h_(5)(n_(B))=("Mass of" CH_(3)COOC_(2)h_(5))/("Molar mass")` `((25g))/((88g mol^(-1))=0.284 mol` No. of moles of `C_(2)H_(5)COOC_(2)H_(5) (n_(A))=("Mass of" C_(2)H_(5)COOC_(2)H_(5))/("Molar mass")` `=((50g))/((102g mol^(-1))=0.49 mol` Mjole fraction of ethyl acetate `(x_(B)) =n_(B)/((n_(A)+n_(B))=((0.284 mol))/((0.28l4mol+0.49 mol))=0.37 ` Mole fraction of ethyl propionate `(x_(A))=n_(A)/(n_(A)+n_(B))=((0.49 mol))/((0.284 mol+0.49))=0.63` Vapour pressure of ethly acetate `(P_(B)^(@))=72.8 mm` Vapour pressure of ethly propionate `(P_(A)^(@))=27.7 mm ` Vapour pressure of ethyl acetate in solution `(P_(B))=P_(A)^(@)x_(A)=(72.8mm)xx0.37=26.94 mm` Vapour pressure of ethyl propionate in solution `(P_(A))==P_(A)^(@)X_(a)=(27.7 mm)xx0.63=12.45 mm` Total vapour pressure of solution =`P_(B)+P_(A)` =26.94mm+17.45mm=44.39 mm |
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