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The vapour pressure of pure benzene at `88^(@)C` is `957 mm` and that of toluene at the same temperature is `379.5 mm`. The composition of benzene-toluene mixture boiling at `88^(@)C` will beA. `x_("benzene")=0.66,x_("toluene")=0.34`B. `x_("benzene")=0.34,x_("toluene")=0.66`C. `x_("benzene")=x_("tolulene")=0.5`D. `x_("benzene")=0.75,x_("toluene")=0.25` |
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Answer» Correct Answer - A `p=p_("benzene")^(0)x_("benzene")+p_("tolulene")^(0)x_("toluene")` `760=957.x_("benzene")+379.5(1-x_("benzene"))` `x_("benzene")=0.66` and`x_("toluene")=1-0.66=0.34`] |
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