1.

The vapour pressure of pure benzene at `88^(@)C` is `957 mm` and that of toluene at the same temperature is `379.5 mm`. The composition of benzene-toluene misture boiling at `88^(@)C` will beA. `chi_("benzene")=0.66 , chi_("toluene") = 0.34`B. `chi_("benzene")=0.34, chi_("toluene") = 0.66`C. `chi_("benzene")= chi_("toluene") = 0.5`D. `chi_("benzene")=0.75, chi_("toluene") = 0.25`

Answer» Correct Answer - a
`p = p_("benzene").^(@)chi_("benzene")+ p_("toluence").^(@)chi_("toluence")`
760= 957


Discussion

No Comment Found

Related InterviewSolutions