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The vapour pressure of pure benzene is `639.7 mm Hg` and the vapour pressure of solution of a solute in benzene at the temperature is `631.9 mm Hg`. Calculate the molality of the solution. |
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Answer» Correct Answer - 0.162 m Solute-B, Benzene-A `"Let molality of solution=X"` `(P^(0)-P_(solution))/(P^(0))=X_(solute)` `(639.7-631.7)/(639.7)=X_(solute)` `m=(X_(solute))/((1-X_(solute)))xx1000/78` `"therefore molality of solution=0.162 m"` |
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