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The vapour pressure of pure liquid solvent A is `0.80`atm.When a non volatile substances B is added to the solvent, its vapour pressure drops to `0.60`atm. Mole fraction of the components B in the solution is:A. `0.50`B. `0.25`C. `0.75`D. gives data is not sufficient |
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Answer» Correct Answer - B `(P^(@) -P_(s))/(P^(@)) = X_("solute")` `X_("solute") = 0.25` |
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