1.

The vapour pressure of water at `23^(@)C` is 19.8 mm of Hg 0.1 mol of glucose is dissolved in `178.2g` of water. What is the vapour pressure (in mm Hg) of the resultant solution?A. `19.0`B. `19.602`C. `19.402`D. `19.202`

Answer» Correct Answer - B
n(glucose) = 0.1
n(water) `= (178.2)/(18) = 9.9`
x(water) `=(9.9)/(9.9+0.1)=0.99`
p(solution) `= p^(@)` (solvent) `xx` x(solvent)
`= (19.8 mm Hg)xx 0.99`
`= 19.602 mm Hg`


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