The vapour pressures of pure liquids A and B are 450 mm and 700 mm of Hg respectivly at 360 K. Calculate the composition of the composition of the liqid mixture if the total vpour pressure is 600 mm of Hg. Also find the compositon of the mixture in the capour phase.

The vapour pressures of pure liquids A and B are 450 mm and 700 mm of

1.	The vapour pressures of pure liquids A and B are 450 mm and 700 mm of Hg respectivly at 360 K. Calculate the composition of the composition of the liqid mixture if the total vpour pressure is 600 mm of Hg. Also find the compositon of the mixture in the capour phase.
Answer» Calculation of the composition of liquid mixture For the two liquids A and B `P_(A)=P_(A)^(@)x_(A),P_(B)=P_(B)^(@)x_(B)=P_(B)^(@)(1-x_(A)),P=P_(A)+P_(B)` `600=450x_(A)+700(1-x_(A))` `600=450x_(A)+700-700x_(A)` `250x_(A)=100 or x_(A)=100/250=0.4.` `x_(B)=1-x_(A)=1-0.4=0.6` Calculation of the mixture in the capour phase `P_(A)=0.4xx450mm=180mm,P_(B)=0.6xx700mm=420 mm`. Mole fraction in the vapour phase may be calculated as : `x_(a)=((180mm))/((600mm))=0.3,x_(B)=((420mm))/((600mm))=0.7`

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The vapour pressures of pure liquids A and B are 450 mm and 700 mm of Hg respectivly at 360 K. Calculate the composition of the composition of the liqid mixture if the total vpour pressure is 600 mm of Hg. Also find the compositon of the mixture in the capour phase.

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