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The velocity of a bullet is reduce from `200 m//s` to `100m//s` while travelling through a wodden block of thickness `10 cm` Assuming it to be uniform, the retardation will beA. `15xx10^(4)m//s^(2)`B. `10xx10^(4)m//s^(2)`C. `12xx10^(4)m//s^(2)`D. `14.5m//s^(2)` |
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Answer» Correct Answer - A From equation of motion `V^(2)+u^(2)+2as`…(1) Where `v` is final velociy, `u` is initial velocity `a` is retardation and `s` is distance travel. Given, `v= 100 m//s, u= 200 m//s` `s=10 cm= 10xx10^(-2)` Putting the numerical values in Eq.(1), we have `:. (100)^(2)= (200)^(2)+2xx1xx10xx10^(-2)` `implies 30000= 2axx10^(-2)` `implies a=(30000)/(20xx10^(-2))` `= -15xx10^(4)m//s^(2)` Minus sign shows negatice acceleration i.e., retardation. |
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