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The velocity of an object increases at a constant rate from 20 m s^(-1) to 50 m s^(-1)in 10 s. Find the acceleration. |
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Answer» Solution :Given u = 20 m `s^(-1), v = 50 m s^(-1), t = 10 s` Acceleration a = `(v-u)/(t) = (50 m s^(-1)-20 m s^(-1))/(10 s )` or ` a= (30 ms^(-1))/(10 s ) = 3 m s^(-2)`. |
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