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The vertices of a Delta ABC are A (4,6), B (1, 5) and C (7,2). A line is drawn to intersect sides AB and AC at D and Erespectively, such that (AD)/(AB) = (AE)/(AC) = (1)/(4).Calculate the area of DeltaADE and compare it with area of Delta ABC

Answer»


ANSWER :`DELTAABC =(1/4)^(2)=1/16`


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