InterviewSolution
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InterviewSolution
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The vertices of a triangle are (0,0), `(x ,cosx),`and `(sin^3x ,0),w h e r e0A. `3sqrt(3)/(32)`B. `(sqrt(3))/(32)`C. `(4)/(32)`D. `6 sqrt(3)/(32)` |
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Answer» Correct Answer - 1 f(x)=`(sin^(3)xcosx)/(2)` `therefore f(x)=(3 sin^(2)xcos^(23)x-sin^(4)x)/(2)` `f(x) =0 rarr 3 sin^(2)x cos^(2)x - sin^(4)x=0` or `3 cos^(2)x-sin^(2)x=0` or `4cos^(2)x-1=0` or `cosx=1/2` or `x=(pi)/(3)` which is the point of maxima `therefore f_(max)=(sqrt(3)//2)^(3)(1//2)/(2)=(3sqrt(3))/(32)` |
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