1.

The Vividh Bharati station broadcasts on a frquency of `1368kHz`. Calculate the wavelength of electromag-netic radiation emitted by the transmitter.

Answer» `lambda = (c )/(v)`
`c=3xx10^(8)ms^(-1),v=1368kHz=1368xx10^(3)Hz("or"s^(-1))`
`therefore " "lambda=((3xx10^(8)ms^(-1)))/((1368xx10^(3)s^(-1)))=219.3m`


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