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The volume of `0.1M H_(2)SO_(4)` required to neutralise completely `40mL` of `0.2M NaOH` solution isA. `10mL`B. `40mL`C. `20mL`D. `80mL` |
Answer» Correct Answer - B `2NaOH + H_(2)SO_(4) rarr Na_(2)SO_(4)+H_(2)O` `(M_(1)V_(1))/(n_(1)) = (M_(2)V_(2))/(n_(2))` `{:((NaOH),(H_(2)SO_(4)).),((0.2xx40)/(2)=,(0.1xxv)/(1)),(" "v=,40mL):}` |
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