The volume of water to be added to `N//2 HCI` to prepare `500 cm^(3)` of `N//10` solution isA. `45cm^(3)`B. `400 cm^(3)`C. `450cm^(3)`D. `100cm^(3)`

The volume of water to be added to `N//2 HCI` to prepare `500 cm^(3)`

1.	The volume of water to be added to `N//2 HCI` to prepare `500 cm^(3)` of `N//10` solution isA. `45cm^(3)`B. `400 cm^(3)`C. `450cm^(3)`D. `100cm^(3)`
Answer» Correct Answer - B `N_(1)V_(1) = N_(2)V_(2)` `(N)/(2) xx V_(1) = (N)/(10) xx 500` `V_(1) = 100` Vol of `N//10` solution `= 500 cm^(3)` Vol. of `N//2` solution `= 100 cm^(3)` `:.` Water to be added `= (500 - 100) cm^(3) = 400 cm^(3)`

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The volume of water to be added to `N//2 HCI` to prepare `500 cm^(3)` of `N//10` solution isA. `45cm^(3)`B. `400 cm^(3)`C. `450cm^(3)`D. `100cm^(3)`

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