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The wave number of the first line in the Balmer series of hydrogen is `15200 cm^(-1)`. What would be the wavenumber of the first line in the Lyman series of the `Be^(3+)` ion?A. `2.4xx10^(5) cm^(-1)`B. `24.3xx10^(5) cm^(-1)`C. `6.08xx10^(5) cm^(-1)`D. `1.313xx10^(6) cm^(-1)` |
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Answer» Correct Answer - D Given `15200=R(1)^(2)[1/((2)^(2))-1/((3)^(2))] ...(1)` Then `bar(v)=R(4)^(2)[1/((1)^(2))-1/((2)^(2))] ...(2)` from (1) and (2) equation `bar(v)=1.313xx10^(6) cm^(-1)` |
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