InterviewSolution
Saved Bookmarks
| 1. |
The wavelength of series limit for lyman series for `He^(o+)` would beA. `911.7 Å`B. `227.9 Å`C. `1215.1 Å`D. `363.8 Å` |
|
Answer» `Z= 2 (for HE^(Theta))` series limit for lyman series `n_(1) =1,n_(2) = oo` `bar v = (1)/(lambda) = RZ^(2)((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) = R(2)^(2)((1)/(1^(2)) - (1)/(oo^(2))) = 4R` `lambda = (1)/(4R)= (1)/(4 xx 109677 cm^(-1)) ` `= 227.9 xx 10^(-10) m = 227.9Å` |
|