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The wavelength of the radiation emitted , when in a hydrogen atom electron falls from infinity to stationary state 1 , would be : (Rydberg constant = `1.097 xx 10^(7) m^(-1)`)A. `91 nm`B. `192 nm`C. `406`D. `9.1xx10^(-6) nm` |
Answer» Correct Answer - 1 `1/lambda=R(1/n_(1)^(2)-1/n_(2)^(2)) 1/lambda=1.097xx10^(7) m^(-1)(1/1^(2)-1/oo^(2)) :. lambda=91xx10^(-9) m=91 m` |
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