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The wavelength of the radiations emitted when in a hydrogen atom electron falls from infinity to stationary state is ` : (R_H = 1. 097 xx10^7 m^(-1))` .A. `9.1 xx 10^-8 nm`B. 192 mC. 406 nmD. 91 nm |
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Answer» Correct Answer - D (d) `(1)/(lamda) = R_H[(1)/(oo) -(1)/(l^2)]` :. `lamda =(1)/(R_H) = (1)/(1.097 xx 10^7) m = 9.1 xx 10^-8 m` =`91 xx 10^s m = 91 nm`. |
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