1.

The weight of `1` curie `._(82)Pb^(214) (t_(1//2)=26.8 min)` in grams isA. `3.1xx10^(-8) g`B. `1.55xx10^(-8) g`C. `6.2xx10^(-8)g`D. `3.1xx10^(-10)g`

Answer» Correct Answer - a
We know that, `(-dN)/(dt) = lambda(6.023xx10^(23)xxw)/(M)`
Here, `(-dN)/(dt)` = 1 curie `= 3.7xx10^(10)dps`
`lambda = (0.693)/(t_(1//2)) = (0.693)/(26.8xx60)s^(-1)`
`:. 3.7xx10^(10) = (0.693)/(26.8xx60)xx(6.023xx10^(23)xxw)/(214)`
or `w = 3.1xx10^(-8)g`


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