1.

The work function for a metal si ` 4 eV`. To emit a photoelectron of zero velocity from the surface fo the metal the wavelength of incident light showld be :A. `2700Å`B. `1700Å`C. `5900Å`D. `3100Å`

Answer» Correct Answer - D
` hv=` "work function" `+ KE `
Given `KE =0` ,
`Thus ` hv = 4e V`
` or ` 4 = ( 12375)/( lambda) ` where `lambda` "is in" `Å`
`thereforelambda = 3100Å`.


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