InterviewSolution
Saved Bookmarks
| 1. |
The work function for a metal si ` 4 eV`. To emit a photoelectron of zero velocity from the surface fo the metal the wavelength of incident light showld be :A. `2700Å`B. `1700Å`C. `5900Å`D. `3100Å` |
|
Answer» Correct Answer - D ` hv=` "work function" `+ KE ` Given `KE =0` , `Thus ` hv = 4e V` ` or ` 4 = ( 12375)/( lambda) ` where `lambda` "is in" `Å` `thereforelambda = 3100Å`. |
|