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The work function of a metal is `4.0 eV`. If the metal is irradiated with radiation of wavelength `200` nm, then the maximum kinetic energy of the photoelectrons would be about.A. `6.4 xx 10^-19 J`B. `3.5 xx 10^-19 J`C. `1.0 xx 10^-18 J`D. `2.0 xx 10^-19 J` |
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Answer» Correct Answer - B (b) `W_0 = 4.0 eV = (hc)/(lamda_0)` =`4 xx 1.6 xx 10^-19 J` `n = 3 xx 10^15 Hz` `6.4 xx 10^-19 J` Now apply `KE = (hc)/(lamda) - (hc)/(lamda_0)` when given `lamda = 200 nm = 2 xx 10^-7 m`. |
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