1.

The x and y coordinates of a particle at any time t is given by x = 7t + 4t^(2) and y = 5t, where x and y are in metre and t in seconds. The acceleration of particle at t = 5s is

Answer»

Zero
`8m//s^(2)`
`20m//s^(2)`
`40m//s^(2)`

SOLUTION :`x=7t+4t^(2)`
`V_(x)=(dx)/(dt)=7+8t`
`a_(x)=(dv_(x))/(dt)=8`
`y=5t`
`V_(y)=(dy)/(dt)=5`
`a_(y)=(dv_(y))/(dt)=0 m//s^(2)`
`a=sqrt(a_(x)^(2)+a_(y)^(2))=sqrt(8^(2)+0)`
`=8 m//s^(2)`


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