InterviewSolution
| 1. |
There are three taps A, B and C in a tank. They can fill the tank in 25 hrs, 20 hrs and 10 hrs respectively. At first all of them are opened simultaneously. Then after 1 hrs, tap C is closed and tap A and B are kept running. After the 4th hour, tap B is also closed. The remaining work is done by tap A alone. Find the percentage of work done by tap A itself?1). 72%2). 70%3). 71%4). 65% |
|
Answer» Tap A can fill the TANK in 25 hrs. Tap B cab fill the tank in 20 hrs. Tap C can fill the tank in 10 hrs. Total volume of the tank filled by 3 pipes = LCM of (25, 20, 10) = 100 units ⇒ Pipe A can fill 4 units of water in 1 hr. ⇒ Pipe B can fill 5 units of water in 1 hr. ⇒ Pipe C can fill 10 units of water in 1 hr. ⇒ Pipe (A + B + C) can fill 19 units of water in 1 hr. According to question, Pipe (A + B + C) are opened for 1 hr, then tap C is closed. ⇒ 19 units of water are filled in the tank. After 4th hr, tap B is also closed ⇒ for 3 hrs, pipe A and B are open ⇒ (4 + 5) × 3 = 27 units of water are filled. ⇒ 100 - (19 + 27) = 54 units of water are filled by tap A alone. Total units of water filled by tap A is 4 × 1 + 4 × 3 + 54 = 4 + 12 + 54 = 70 units ∴ Percentage of work DONE by tap A = 70% |
|