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There are two radio nuceli `A` and `B. A` is an `alpha` emitter and `B` a `beta` emitter. Their disintegration constant are in the ratio of `1:2` What should be the ratio of number of atoms of `A` and `B` at any time t so that probabilities of getting alpha and beta particles are same at that instant?A. `2:1`B. `1:2`C. `e`D. `re^_(1)` |
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Answer» Correct Answer - a `lambda_(A) lambda_(B) =(1)/(2)` Probabilites of getting `alpha`- and `beta`- particles are same. Thus, rates of disintegration are equal. `:. lambda_(A) N_(A) =lambda_(B) N_(B)` or `(N_(A))/(N_(B)) = (lambda_(B))/(lambda_(A))=2` . |
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