1.

Theweightof a molecule of the compoundC_(60 ) H_(122)is :

Answer»

`1.4xx 10 ^(-21)g`
`1.09 XX 10 ^(-21) g `
`5.025xx 10 ^(23)g `
`16.023 xx 10 ^(23) g `

Solution :Massof 1 molecule `C _(60) H_(122)`
`=("Moleculesmass " xx"No… OFPARTICLES ")/( "Avagardro's No .")`
`= 842xx 6.023xx 10 ^(23)`
`=139.797xx 10^(-23) = 1.39797 xx 10 ^(-21)` g
` C_(60 )H_(122) = 12xx60+1xx122`
`= 720 +122= 842`


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