1.

Three block of masses m_1, m_2 & M_3 are connected by mass less stings as shown on a frictionless table. They are pulled with a force T_(3)=40N," If "m_(1)=10kg, m_(2)=6kg & m_(3)=4kg, then tension T_(2) will be

Answer»

20N
40N
10
32N

Solution :NET acceleration `=(T_(3))/(m_(1)+m_(2)+m_(3))=40/20=2m//s^(2)`
`T_(2)=(m_(1)+m_(2))a=16 XX 2=32N`


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