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Three blocks of masses m_1= 10 kg, m_2= 20kg are connected by strings on smooth horizontal surface and pulled by a force of 60 N. Find the acceleration of the system and frictions in the string. |
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Answer» Solution :All the blocks more with common acceleration a under the force F = 60 N. `F= (m_1 + m_2 + m_3)a` `a=(F)/((m_(1)+m_(2)+m_(3))=1m//s^(2)` To determine, `T_1 to` Free body DIAGRAM of mass `m_1.` `T_1= m_1a = 10xx 1= 10 N` To determine, `T_2 -` Free body diagram of `m_3.` `F-T_(2)=m_3a` SOLVING, we get `T_(2)=30N` |
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