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Three laser guns labelled as I,II&III have power 2 watt, 3watt and 5 watt (not necessarily in same order) are used to produce photocurrent from nmental plate as show in diagram. Number of photons emitted by laser guns are `4xx10^(18),5xx10^(18)` and `9xx10^(18)` per sec. metal plante have thershold energy `4.5` `xx10^(-19) J`. Neither the power nor the number of photon emitted b a particlar laser gun is known and it is know that call all capable emits a photonelectron. Minimum photocurrent which must be passed thought the circuit.A. 2.88B. 1.44C. 2.08D. 0.64 |
Answer» Correct Answer - D For minnimum photocurrenth the combination is follows is as follows (a) `2 wattrArr 5xx10^(18)` photons/sec. ltbgt (b) `3 wattrArr 9xx10^(18)` photons/sec. (c) `5 watt rArr 4xx10^(18)` photons /sec. Combination (a) &(b) does not given any photoelectron only combination (c) will produce [photoelectron . `therefore` photocurrent =`4xx10^(18)xx1.6xx10^(-19)` Amp. ` =0.64` Amp. |
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