Three resistors of 1Omega, 2 Omega and 4Omega are connected in parallel in a circuit. If a 1Omega resistor draws a current of 1A, find the current through the other two resistors.

Three resistors of 1Omega, 2 Omega and 4Omega are connected in paralle

1.	Three resistors of 1Omega, 2 Omega and 4Omega are connected in parallel in a circuit. If a 1Omega resistor draws a current of 1A, find the current through the other two resistors.
Answer» Solution :`R_(1)=1OMEGA,R_(2)=2Omega,R_(3)=4Omega`, Current `I_(1)=1A` The potential DIFFERENCE across the `1Omega` RESISTOR `=I_(1)R_(1)=1xx1=1V` since, the RESISTORS are connected in parallel in the circuit, the same potential difference will exist across the other resistors also. So, the current in the `2Omega` resistor, `(V)/(R_(2))=(1)/(2)=0.5A` Similarly, the current in the `4Omega` resistor `(V)/(R_(3))=1/4=0.25A`