1.

Three resistors of resistance 5 ohm, 3 ohm and 2 ohm are connected in series with 10 V battery. Calculate their effective resistance and the current flowing through the circuit.

Answer»

Solution :`R_(1)=5OMEGA,R_(2)=3OMEGA,R_(3)=2OMEGA,V=10V`
`Rs=R_(1)+R_(2)+R_(3)`,
`R_(s)=5+3+2=10`, hence
`R_(s)=10Omega`
The current, `I=(V)/(R_(s))=(10)/(10)=1A`


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