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Three resistors of resistances 2 Omega, 3 Omega and 5 Omega are connected in series with 10 V battery. The voltage across 2Omega resistor will be ………………… .

Answer»

`10 V`
`5 V`
`3 V`
`2 V`

Solution : The equivalent resistance of the circuit
`R = 2 +3 +5 = 10 Omega`
The current FLOWING through the circuit
`I = V/R = 10 /10 = 1A`
The VOLTAGE across `2 Omega` resistor
`= 2 XX I = 2OMEGA xx 1A = 2V`


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