Threshold frequency of metal is `f_(0)`. When light of frequency `v = 2f_(0)` is incident on the metal plate, velocity of electron emitted in `V_(1)`. When a plate frequency of incident radiation is `5f_(0), V_(2)` is velocity of emitted electron, then `V_(1):V_(2)` isA. `1:4`B. `1:2`C. `2:1`D. `4:1`

Threshold frequency of metal is `f_(0)`. When light of frequency `v =

1.	Threshold frequency of metal is `f_(0)`. When light of frequency `v = 2f_(0)` is incident on the metal plate, velocity of electron emitted in `V_(1)`. When a plate frequency of incident radiation is `5f_(0), V_(2)` is velocity of emitted electron, then `V_(1):V_(2)` isA. `1:4`B. `1:2`C. `2:1`D. `4:1`
Answer» Correct Answer - B `K.E. = h (v-v_(0)) Ϸ (1)/(2)mv^(2) = h(v-v_(0))` `v^(2) = (2h(v-v_(0)))/(m), v_(1)^(2) = (2h(2f_(0)-f_(0)))/(m)` ...(1) `v_(2)^(2) = (2h(5f_(0)-f_(0)))/(m)`...(2)

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