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Time taken by an electrons to complete one revolution in the Bohr orbit of the `H` atom isA. `(4pi^2mr^2)/(nh)`B. `(nh)/(4pi^2 mr)`C. `(nh)/(4pi^2 mr^2)`D. `h/(2pimr)` |
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Answer» Correct Answer - A It will take `(4pi^2mr^2)/(nh)` |
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