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To determine the half life of a radioactive element , a student plote a graph of in `|(dN(t))/(dt)| versus t , Here |(dN(t))/(dt)|` is the rate of radioatuion decay at time t , if the number of radoactive nuclei of this element decreases by a factor of p after `4.16 ` year the value of p is A. `5319`B. `5422`C. `5707`D. `5818` |
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Answer» Correct Answer - 8 `N =N_0 e^(-lambda t)` `ln|dN|dt|=1n(N_0 lambda)-lambda t` From graph `lambda =(1)/(2)` per year `(t_(1))/(2)=(0.693)/(1//2)=1.386` year `4.16` years `=3t_(1//2)` `p=8`. |
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