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To generate a power of `3.2` mega watt, the number of fissions of `U^235` per minute is. (Energy released per fission `= 200 MeV, 1 eV = 1.6 xx 10^-19 J`).A. `6 xx 10^18`B. `6 xx 10^17`C. `10^17`D. `6 xx 10^16` |
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Answer» Correct Answer - A (a) Number of fission per second `=("Power output")/("Energy released per fission")` `=(3.2 xx 10^6)/(200 xx 10^6 xx 1.6 xx 10^-19) = 1 xx 10^17` rArr Number of fission per minute `=60 xx 1 xx 10^17 = 6 xx 10^18`. |
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