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To neutralise completely 20 mL of 0.1 M aqueous solution of phosphrous acid `(H_(3)PO_(3))`, the volume of 0.1 M aqueous KOH solution required is :A. 40 mLB. 20 mLC. 10 mLD. 60 mL |
Answer» Correct Answer - a Since `H_(3)PO_(3)` is dibasic, 0.1 M solution =- 0.2 N solution. `underset(("Acid"))(N_(1)V_(1))=underset(("Base"))(N_(2)V_(2))` `(0.2 N)xx20 mL)=(0.1N)xxV_(2)` `V_(2)=((0.2N)xx(20mL))/((0.1N))=40 mL.` |
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