

InterviewSolution
Saved Bookmarks
1. |
To produce an electron-position pair, the minimum energy of `gamma`-ray photon must beA. `1.02keV`B. `1.02MeV`C. `1.02BeV`D. `1.02eV` |
Answer» Correct Answer - B Rest energy of electron `= (9.1xx10^(-31)xx(3xx10^(8))^(2))/(1.6xx10^(-13))MeV` `= 0.510 MeV` `gamma rarr e^(+) +e^(-)` Energy of photon `= 2xx0.51 = 1.02MeV` |
|