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triangle ABC~triangle LBN. In triangleABC, AB=5.1 cm, /_B=40^(@), BC=4.8 cm, (AC)/(LN)=(4)/(7). Construct triangle ABC " and"triangle LBN.

Answer»


Answer :If seg BC is DIVIDED into 4 EQUAL parts, then seg BN will be 7 times each part of seg BC.
So, if we construct `triangle ABC`, point N will be on side BC, at a distance equal to 7 parts from B.
Now, point L is the point of INTERSECTION of ray BA and a line through N, PARALLEL to AC.
`triangle LBN` is the required triangle similar to `triangle ABC`.


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