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Two blocks of masses 8 kg and 2 kg respectively, lie on a smooth horizontal surface in constant with one other. They are pushed by a horizontally applied force of 15 N. Calculate the force exterted on the 2 kg mass.

Answer»

Solution :Given: `m_(1)=8KG, m_(2)=2kg, F=15N`
`F=m_("total"), F=(m_(1)+m_(2))a=(8+2)a=10a`
`15=10 a RARR a=(15)/(10)=(3)/(2)MS^(-2)`
`therefore"Force exerted by MASS of 8kg"`
`F_(1)=m_(1)=a=8xx(3)/(2)=12N`


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