1.

Two bulbs have ratings 100 W, 220 V and 60 W, 220 V. Which one has the greater resistance ?

Answer»

Solution :Resistance of FIRST BULB `R_(1)=(V^(2))/(P)=(22cancel(theta)xx22cancel(theta))/(cancel(100))=484Omega.`
Resistance of second bulb `R_(2)=(V^(2))/(P)=(220xx22cancel(theta))/(6cancel(theta))=(4840)/(6)=806.6Omega.`
`THEREFORE` The bulb rated 60 W,220V has the greater resistance.


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