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Two copper spheres of equal mass, one solid and the other hollow, are heated through an equal rise in temperature. What is the ratio of the time taken to heat them if the ratio of the rate at which heat is upplied to the solid sphere to hollow sphere is 1:2 ? |
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Answer» Solution :(i) Given that the two spheres are of same material and have equal mass. `rArr"the density "(rho)` and mass (m) of the spheres is constant. Equal rise in temperature `rArr Delta theta ` is constant. RATE of heat supplied (K) `=("Heat supplied (Q)")/("time (t)")` `rArr""Q=Kt"(1)"` `"Also "Q=ms Delta theta"(2)` where 's' is the SPECIFIC heat capacity (in this case it is same for both the spheres) EQUATE (1) and (2) and apply it for both the spheres. From the equations applied find the ratio of time TAKEN to heat spheres. (ii) 2:1 |
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